Ex5 12

$\def\abs#1{|#1|}\def\i{\mathbf {i}}\def\ket#1{|{#1}\rangle}\def\bra#1{\langle{#1}|}\def\braket#1#2{\langle{#1}|{#2}\rangle}\def\tr{\mathord{\mbox{tr}}}\mathbf{Exercise\ 5.12}$

Design a circuit that constructs the Hardy state $\frac{1}{\sqrt{12}} (3\ket{00} + \ket{01} + \ket{10} + \ket{11}).$